Calculations for AS and A level Chemistry
Being confident in tackling different types of mole calculation is the foundation upon which much of A level chemistry stands
The ultimate A level chemistry resource

Being confident in tackling different types of mole calculation is the foundation upon which much of A level chemistry stands
This is a set of more difficult long answer exam questions that require you to use data from mass spectra,
Continue readingMixed spectra long answer exam question practice
25th October 2025 Are you leveraging the A* advice in mark schemes? Using past paper mark schemes to help you
Your may have noticed on the data sheet that the wavenumber for the absorption of C=O bonds very much depends
Continue readingExplaining C=O absorption bands in IR spectroscopy
An IR spectrum plots of the percentage of radiation that passes through a sample (transmittance) vs. the wavenumber of the
Infrared spectroscopy is a really useful analytical technique for determining whether there are key bonds in a molecule (C=O, O-H,
13C NMR signals are considerably weaker than 1H NMR signals because the natural abundance of 13C is 1.1%. We also
Continue readingEverything you need to know about C-13 NMR spectroscopy
In proton or 1H NMR spectroscopy the sample is dissolved in a solvent such as tetrachloromethane, CCl4, or trichlorodeuteriomethane, CDCl3
Continue readingEverything you need to know about proton (H-1) NMR Spectroscopy
We are familiar with the idea that electrons possess an intrinsic quantum property known as spin (we met this when
Continue readingUnderstanding nuclear magnetic resonance spectroscopy
We can cause a sparingly soluble salt to precipitate out of solution if the product of the concentration of the
Silver chloride is a sparingly soluble salt. AgCl(s) ⇌ Ag+(aq) + Cl–(aq) Ksp = [Ag+(aq)] [Cl–(aq)] = 2.0 x 10-10
Many ionic compounds are sparingly soluble – a good example is barium sulphate which has a solubility of 1.05 x
We can derive a value for the equilibrium constant in a gaseous equilibrium system either using partial pressures, Kp, or
Continue readingUnderstanding the relationship between Kc and Kp